Best Title Line Have Ever Seen in an Online Profile

[furrbear]

∀ε>0 ∃δ>0 ∋ 0<|x-a|<δ⇒|ƒ(x)-L|<ε

Points if you can identify it.

Comments screened until tomorrow.

Comments

[squirreltot.livejournal.com]

Let's get together (converge)? Where do you find these profiles? geekbear.net?

[furrbear.livejournal.com]

It's a LJ profile. And that's not the answer we're looking for.

[squirreltot.livejournal.com]

Dang...looked like a limit of some sort, but it has been WAY too long since I had any kind of math class. I look forward to seeing the answer tomorrow.

[furrbear.livejournal.com]

looked like a limit of some sort

So-o-o-o-o-o-o close

[lucentnotion.livejournal.com]

something in calculus dealing with limits...

but I SOOOOO googled that formula!

[fzks-cub.livejournal.com]

looks like the epsilon/delta definition of the limit of a function as x approaches a constant... or lim(x->a) f(x) = L spelled out in math symbols

calculus ftw

[furrbear.livejournal.com]

Close enough. Weierstrass Definition of a Limit

[westwind-mv.livejournal.com]

It's the definition of the limit of a continuous function:

"For any positive epsilon there exists a positive delta such that for a deleted neighborhood of x within delta the value of the function will approach the limit L within epsilon."

Man, my calculus is rusty...

[trulygrateful.livejournal.com]

IIRC, isn't this the formal definition of Limit?

[dakoopst.livejournal.com]

Isn't that the rigorous definition of a limit in calculus?

[perlcub]

Not quite sure what it is, but I can only "read" half of it... And what I found was that it's something about defining a mathematical limit in terms of the function f(x)?

What's funny, though, is the result of the google search. At the bottom, it asks it's "did you mean"... It make me chortle!

Edit: It seems as if Google wants to say that it could help me out better only if the expression read "for the absolute values of x" rather than for "a from x". Ha!

[texaspenguin.livejournal.com]

For each e > 0 there exists a delta > 0 such that for every x with 0 < |x-a| < delta, the value of |f(x) - L| is less than e.

...it's the definition of a limit.

But the limit of a function as x approaches a is L. How is that an online profile header?

Hrmm...

[furrbear.livejournal.com]

see Journal Recent Posts belonging to commenter below

[jrjarrett.livejournal.com]

For every epsilon > 0 there is a delta >0 such that the absolute value of x-a > 0 and less than delta implies that the absolute value of f(x) -L < epsilon.

The basis of limits in calculus.

oh wait, that's MY profile :D

You get double super extra bonus points if you can give me the logical negation of that statement.

(I don't know the answer; it was a bonus question in my Honors Calc I class, and we never got it right...it's haunted me for 25 years)

[greatbearmd.livejournal.com]

jrjarrett

[cipherpunk.livejournal.com]

Unless I miss my guess, that’s a reasonable definition of a limit.

[geometrician.livejournal.com]

This would be my good friend and neighbor, jrjarrett. It is a mathematical definition of a limit.

[qbear.livejournal.com]

it's my friend jrjarrett's

[woofytexan.livejournal.com]

I have this on a t-shirt. You can get it at Think Geek.